9 ayst123



TA的排名 1w+

Git, Misc

不用每次输入账号和密码的方法对单个 repo 设置 user.name 和 user.emailaddress不用每次输入账号和密码的方法 git config credential.helper store git push https://github.com/repo.git Username for ‘https://github....

2018-05-10 14:59:51


2018-05-10 08:09:49


1.安装 cuda 8.0 直接官网安装即可,cuda 8.0 中自带 gpu driver. 所以不用提前装 driver. 注意安装 cuda 8.0 时,不要装 xconfigure, opengl。 在网上看到据说什么用。装 cudnn, 比较简单。 貌似得下 linux 版本,而不用选 ubuntu 版本编译 caffe 时说找不到 /usr/bin/ld: cannot fin

2017-01-20 13:11:43

Others, Academic

经验和分享Yoshua Bengio 研究生科研指导演讲:解读人工智能全貌和下一个前沿基础Back-propagation无监督深度学习基础, by Ruslan SalakhutdinovAttention based model 是什么,它解决了什么问题? - 知乎深度学习如何入门迁移学习综述VAE条件变分自编码器数学蒙特卡罗哈密顿方法(交互式)详解前沿机器学习对抗性攻

2017-01-11 13:39:57

Reinforcement Learning

理解增强学习的解释, English

2017-01-11 12:50:57

GAN: Generative Adversarial Network

理解独家​|深度学习新星:GANs的基本原理、应用和走向, 冯佳时

2017-01-11 12:49:01

Interested Papers

Dec 4 1. https://arxiv.org/pdf/1612.00835.pdf 2. https://arxiv.org/pdf/1612.00500.pdf 3. https://arxiv.org/pdf/1612.00522.pdf 4. https://arxiv.org/pdf/1612.00593.pdf 5. https://arxiv.org/pdf/1612.

2016-12-05 13:54:11

Codility: EvenSumsGame

QuestionEven sums is a game for two players. Players are given a sequence of N positive integers and take turns alternately. In each turn, a player chooses a non-empty slice (a subsequence of consecuti

2016-05-08 14:11:50

C++ 引用传递

以前对引用传递一知半解,尤其是 & 符号。现在做一下梳理。Get idea from here.先来看下 alias: int i = 5;int &j = i; // j is an alias to ij = 5;这里 j 就是 i 这个变量的另一个名字。所以这个对象现在有两个名字 i 和 j. 现在就好理解引用传递了。用这种方法,形参就变成了实参的一个 alias. 1 #include<

2016-02-09 07:51:14

Python Closure 闭包

Summaryglobals locals闭包闭包需要注意的地方1 不能在闭包中引用任何会改变的变量2闭包的应用1 为英语增加复数形式的代码Summary闭包就是函数和它的环境(变量) 1. 尽量把 closure 中的变量变成 local 变量1. globals, localsCitation先来说下作用域,一共有三种作用域 – l

2016-02-01 08:43:16

Python Decorators 装饰器

QuestionA group of two or more people wants to meet and minimize the total travel distance. You are given a 2D grid of values 0 or 1, where each 1 marks the home of someone in the group. The distance i

2016-02-01 04:11:59

Python Skills

Summarythe peculiar nature of and and or1 andorConditional Assignmentset builtinSummaryavoid "for" and "if-and-else" instead, use list comprehension and conditional assignmentfs1. the pecul

2016-01-31 11:01:27

Leetcode: Maximum Product of Word Lengths

QuestionGiven a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower ca

2016-01-05 10:11:28

Leetcode: Shortest Distance from All Buildings

QuestionShortest Distance from All Buildings My Submissions Question Total Accepted: 919 Total Submissions: 3251 Difficulty: Hard You want to build a house on an empty land which reaches all buildin

2016-01-05 09:13:29

leetcode, Range Sum Query - Mutable

class NumArray(object): def __init__(self, nums): """ initialize your data structure here. :type nums: List[int] """ self.nums = [0]*len(nums)

2016-01-03 12:42:04

Leetcode: Range Sum Query - Mutable

#Question Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.The update(i, val) function modifies nums by updating the element at index i to val. Exa

2016-01-02 10:52:53

Leetcode: Coin Change

QuestionYou are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of

2015-12-30 12:32:23

Leetcode: Range Sum Query - Immutable

QuestionGiven an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.Example: Given nums = [-2, 0, 3, -5, 2, -1]sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRa

2015-12-30 10:45:19

Leetcode: Range Sum Query 2D - Immutable

QuestionRange Sum Query 2D - Immutable My Submissions Question Total Accepted: 5239 Total Submissions: 25173 Difficulty: Medium Given a 2D matrix matrix, find the sum of the elements inside the rect

2015-12-30 10:39:04

Leetcode: Smallest Rectangle Enclosing Black Pixels

QuestionAn image is represented by a binary matrix with 0 as a white pixel and 1 as a black pixel. The black pixels are connected, i.e., there is only one black region. Pixels are connected horizontall

2015-12-28 18:16:36


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